Learning The Pythonic Way

Some cool features and tips to write more Pythonic code

Photo by Tudor Baciu on Unsplash
The Zen of Python

Here are a few practices and features that will help you write idiomatic and Pythonic code:

  • Naming Conventions: The PEP8 (Python Enhancement Proposal) guidelines suggest some specific naming conventions such as:
Naming Conventions in Python
  • Multiple Assignment and Iterable Unpacking: Python supports assigning the same values to multiple variables. For example:
# assigning a and b as 100a = b = 100
# Iterable UnpackingX Not recommendedemployees = ["Carlos", "Badal", "Manoj"]
first = employees[0]
second = employees[1]
third = employees[2]
=> Recommendedfirst, second, third = employeesXX ValueError: too many values to unpack if : first, second, third = ["Carlos", "Badal", "Manoj", "Michael"] XX ValueError: not enough values to unpack if :first, second, third = ["Carlos", "Badal"]
# Unpacking generators
result = (i ** 3 for i in range(5))
zero, one, two, three, four = result

# Unpacking a dictionary
dicts = {'one': 1, 'two':2, 'three': 3, ‘four’:4} * This will unpack keysa, b, c, d = dicts* This will unpack valuesa, b, c, d = dicts.values() * This will unpack (key, value) pair a, b, c, d = dicts.items()
# Using * operator
a, *b = 1, 2, 3
=> a = 1 => b = [2,3]
first, *second, third = [1,2,3,4,5]
=> first = 1 => second = [2,3,4] => third = 5

# Swapping values
X Not recommendedtemp = a
a = b
b = temp
=> Recommendeda, b = b, aVery useful in sorting tasks while doing:
a[i-1], a[i] = a[i], a[i-1]
  • Comparison: To avoid confusion in identity and equality comparison, you should be clear on ‘is’ (identity comparison) and ‘==’ (value comparison). In Python, ‘is’ returns true if two references refer to the same object and ‘==’ returns true if two objects have the same value.
a = [1, 2, 3, 4]b = a=> b is a
returns True
=> b == a
returns True
But if we make a new copy of a and compare:b = a[:]=> b is a
returns False
=> b == a
returns True
  • Loops: Using methods such as enumerate and zip with loops, we can simplify our program.
# Enumerate Allows you to keep track of index along with variable while looping throuh an iterable:employees = [‘Carlos’,’Badal’,’Michael’]X Not recommendedfor idx in range(len(employees)): 
=> Recommendedfor idx, name in enumerate(employees):
# ZipAllows you to easily work with multiple lists of related data:employees = [‘Carlos’,’Badal’,’Michael’]
age_records = [25, 26, 27]
for name, age in zip(employees, age_records):
print(f"{name} is {age}.")
  • List Comprehension: This is one of my favorite features in Python for its elegance and readability. It is much easier to understand for beginners and also performs faster than its alternatives most of the time.
X Not Recommendedresult = []for i in range(5):
=> Recommendedresult = [i**3 for i in range(5)]
* We can do so much moredicts = {‘james’: '100', 'donna’: '200', 'smith': '50'}
result = [dicts[x] for x in dicts]
a = [1, 2, 3]
b = [4, 5, 6]
result = [x - y for x in a for y in b]

# Nested List Comprehension
a = [[1,2],[3,4],[5,6]]b = [x for each in a for x in each]=> b will be [1, 2, 3, 4, 5, 6]
  • Avoid Map, Filter & Reduce (whenever possible): Map, Filter & Reduce functions bring a bit of functional programming to Python providing a short-hand approach to some problems and can be replaced with list comprehension and loops.
# map()Map is still very useful when performing a task like this:map(str, range(100))instead of:[str(item) for item in range(100)]
But :=> Recommended: List Comprehension[expression(item) for item in iterable]
or, (expression(item) for item in iterable) -> generator expressions
X Not Recommendedmap(lambda item: expression(item), iterable)
# filter():def some_function(x):
return x % 2 != 0 and x % 3 != 0
X Not Recommendedresult = list(filter(some_function, range(2, 25)))=> Recommened: List Comprehensionresult = [i for i in range(2,25) if some_function(i)]
X Not Recommendedlist(map(lambda x:x+1, filter(lambda x:x%3, range(10))))=> Recommended: List Comprehension[x+1 for x in range(10) if x%3]
my_list = [10,15,20,25,35]X Not Recommendedfrom functools import reduce
total_sum = reduce(lambda x ,y : x+y , my_list)
=> Recommendedtotal_sum = 0for num in my_list:
total_sum += num
or, total_sum = sum(my_list)




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